"""
Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg", "add", return true.

Given "foo", "bar", return false.

Given "paper", "title", return true.

Note:
You may assume both s and t have the same length.
"""


class Solution(object):
    def isIsomorphic(self, s, t):
        """
        :type s: str
        :type t: str
        :rtype: bool
        """
        d1, d2 = {}, {}
        for i, val in enumerate(s):
            d1[val] = d1.get(val, []) + [i]
        for i, val in enumerate(t):
            d2[val] = d2.get(val, []) + [i]

        return sorted(d1.values()) == sorted(d2.values())


if __name__ == "__main__":
    s = Solution()
    print s.isIsomorphic("egg","add")
